2[2(s+2)-2]=4s+4

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Solution for 2[2(s+2)-2]=4s+4 equation: 


Simplifying
2[2(s + 2) + -2] = 4s + 4

Reorder the terms:
2[2(2 + s) + -2] = 4s + 4
2[(2 * 2 + s * 2) + -2] = 4s + 4
2[(4 + 2s) + -2] = 4s + 4

Reorder the terms:
2[4 + -2 + 2s] = 4s + 4

Combine like terms: 4 + -2 = 2
2[2 + 2s] = 4s + 4
[2 * 2 + 2s * 2] = 4s + 4
[4 + 4s] = 4s + 4

Reorder the terms:
4 + 4s = 4 + 4s

Add '-4' to each side of the equation.
4 + -4 + 4s = 4 + -4 + 4s

Combine like terms: 4 + -4 = 0
0 + 4s = 4 + -4 + 4s
4s = 4 + -4 + 4s

Combine like terms: 4 + -4 = 0
4s = 0 + 4s
4s = 4s

Add '-4s' to each side of the equation.
4s + -4s = 4s + -4s

Combine like terms: 4s + -4s = 0
0 = 4s + -4s

Combine like terms: 4s + -4s = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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